16x^2+10=82x

Solution for 16x^2+10=82x equation:

16x^2+10=82x

We move all terms to the left:

16x^2+10-(82x)=0

a = 16; b = -82; c = +10;
Δ = b2-4ac
Δ = -822-4·16·10
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-82)-78}{2*16}=\frac{4}{32}
=1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-82)+78}{2*16}=\frac{160}{32}
=5
$